never taylor expanded a term this large, would appreciate some help2) Consider a particle trapped in a square well that ranges from x = 0 to x=L. The particle has mass m
and velocity V,. Now, add a potential to this square well of
mvz ( 1
while keeping the velocity v, when the particle is at x = 0.
a. Find an approximate solution to the problem by expanding the integral:
ſdt = 5
as was done in class.
2 (E-V(x))
b. With this simple potential, you can also solve this problem exactly, using Newton’s Law. Do so,
and compare the exact solution to your approximate solution.

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